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1. int sum = add every digit of n, since n is at most 2,000,000,000, sum has two digits at most.
2. int temp = sum/10 + sum %10
3. if temp < 10, print temp
else print temp / 10 + temp % 10
![:D](./images/smilies/icon_biggrin.gif)
Code: Select all
1. int sum = add every digit of n, since n is at most 2,000,000,000, sum has two digits at most.
2. int temp = sum/10 + sum %10
3. if temp < 10, print temp
else print temp / 10 + temp % 10
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7
1 2 2 3 4 5 7
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2 3 1
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3 1 1
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char k=1;
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int k=1;